Question

the value of machine depreciates every year by 8%. what will be its value after 2 year if its present value is rupees 25000​

Answer 1

Step-by-step explanation:

Amount = P(1-r/100) square

A = 25000(1-8/100) square

Take LCM

A = 25000(92/100) square

A = 25000(92/100)× (92/100)

A = 25000 × 92/100×92/100

A = 21,160

Answer 2

I HOPE MY ANSWER HELPS YOU!

Answer: Rs. 21000

Step-by-step explanation:

P.A. (per annum) loss rate: 8%

Present value: Rs. 25000

Value of money after 2 years: (8% of 25000) x 2 - 25000

= 8% of Rs.25000

= 8 / 100 x 25000

= 8 / 1 x 250 (After cancellation of the zeroes)

= Rs. 2000 x 2

= Rs. 4000

= Rs. 25000 - Rs. 4000

= Rs. 21000

PLEASE DON'T FORGET TO MARK THIS ANSWER AS THE BRAINLIEST!!!