Question

The value of machine reduces every year by 8%.if the present value of the machine be Rupees 200000,then what will be its value after 2 years​

Answer 1

Answer:

P=200000

R=8pecent

T=2yrs

Step-by-step explanation:

A=P(1+R/100)2

=200000(1+8/100)2

=200000(108/100)2

=200000×108×108÷100÷100

=20×108×108

=233280