the value of of (sin65+sin25)÷(cos65+cos25)
Answers
Answered by
0
(sin65+sin25)÷(cos65+cos25)
=[Sin65°+(Cos90-65)]÷[Cos65°+(Sin90-65)]
=(Sin65°+Cos65°)÷(Cos65°+Sin65°)
=Sin65°÷Cos65°+Cos65°÷Sin65°
=Tan65°+Cot65°
=[Sin65°+(Cos90-65)]÷[Cos65°+(Sin90-65)]
=(Sin65°+Cos65°)÷(Cos65°+Sin65°)
=Sin65°÷Cos65°+Cos65°÷Sin65°
=Tan65°+Cot65°
Similar questions
CBSE BOARD XII,
7 months ago
Math,
7 months ago
English,
1 year ago
Math,
1 year ago
English,
1 year ago