Question

the value of p(2) for p(y)= 2y^3-y^2-13y-6​

Answer 1

Answer:

-20

Step-by-step explanation:

in photo............

Answer 2

Step-by-step explanation:

p(y) =

$2 {y}^{3} - {y }^{2} - 13y - 6$

To get p(2), we need to substitute 2 in the place of y in p(y)

p(2) =

$2 {(2)}^{3} - {(2)}^{2} - 13(2) - 6$

=

$2(8) - (4) - (26) - 6$

=

$16 - 4 - 26 - 6$

= -20

Therefore, the value of p(2) is '-20'.

Hope it helps you.

Good Luck.