Question

The value of p for the equation 2x^2-4x+p=0 to have real roots will be

Answer 1

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$2 {x}^{2} - 4x + p = 0$

Formula

${b}^{2} - 4ac = 0$

b=(-4), a=2,c=p

${ - 4}^{2} - 4(2)(p) = 0$

$16 - 8p = 0 \\ 16 = 8p \\ 2 = p \: \: \: \: \: ans..$

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