Question

The value of p for which (2p+1),10 and (5p+5) are three consecutive terms of an AP is
a. -1
b. -2
c. 1
d. 2

Answer 1

Answer:

Step-by-step explanation:

10-(2p+1)=5p+5-10

9-2p=5p-5

7p=14

p=2

Answer 2

The value of 'p' is 2

Given:

(2p+1), 10, and (5p+5) are three consecutive terms of an AP  

To find:

The value of p  

Solution:

Condition used:

When 3 terms of an ap are a, b, c,

Here,  b - a = c - b   [ since the common difference is equal ]

=> b + b = a + c

=> 2b = a + c  we use this condition to solve the following problem

Given that

(2p+1), 10, and (5p+5) are three consecutive terms of an AP  

By the given condition

=> 2(10) = 2p + 1 + 5p + 5

=> 20 = 7p + 6

=> 7p = 14

=> p = 2

Therefore,

The value of 'p' is 2

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