Question

The value of P for which the points (–5, 1), (1, –1) and (P, –2) are collinear, is

Answer 1

Answer:

the value of p for which the points are collinear = ar∆=0

ar∆= 1/2|X1(y2-y3)+X2(y1-y3)+X3(y2-y1)|

here X1= -5 X2= 1 X3=p

y1=1 y2= -1 y3= -2

ar∆= 1/2| -5(-1-(-2))+1(1-(-2)+p(-1-1)|

0= 1/2|-5(1)+1(3)-2p|

0= -5+3-2p

0= -2-2p

-2p = 2

p = -1

Answer 2

Answer:

when the points are given collinear it means the area of the given triangle is equal to 0

P=4

Step-by-step explanation:

i hope it helps you