Math, asked by omp79117, 8 months ago

The value of p so the quadratic equation x^2+5px+16=0 has no real roots

Answers

Answered by DarkWillow
2

Answer:

Step-by-step explanation:

Discriminant <0, means no real roots

(5p)^{2} - 4*1*16 &lt; 0

25p^{2} &lt;64

p &lt; \sqrt{\frac{64}{25} }

p &lt; \frac{8}{5}

Answered by hhdharod
2

 {b}^{2}  - 4ac

let a = 1

b = 5p

c = 16

25p2 - 4*1*16

25p2 - 64

25p2= 64

P2 = 64/25

p =√64/25

p= 8/5

hope it helps you

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