Question

The value of p(t) = 2+t+2t2−t3 when t=0 is​

Answer 1

Answer:

p(t) = 2+t+2t^2−t^3

So

p(0) = 2+0+2 × 0^2−0^3 = 2 +0+0-0=2

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Answer 2

Answer:

p(t)=2+t+2t^2-t^3

=2+0+0-0

=2

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