Question

The value of p(x)=(x-1)(x-1) for p(1) is?? I will mark it as brainlist :)

Answer 1

Answer:

answer will be 0

p(1)=(1-1)(1-1)

p(1)=(0)(0)

p(x)=0

Answer 2

Given: $p(x)=(x-1)(x-1)$

we have to find $p(x)$ at $x=1$ that is $p(1)=?$

put $x=1$ in $p(x)$, we get:

$p(x)=(x-1)(x-1)$

$p(1)=(1-1)(1-1)$

$p(1)=(0)(0)$

$p(1)=0.$