Question

The value of phase at maximum displacement from the mean position of a particle in shm is

Answer 1

Answer: $\phi = \dfrac{\pi}{2}$

Explanation:

We know that,

The equation of SHM

$y = A sin(\omega t + \phi)$

Where,

y = displacement

A = amplitude

t = time

$\phi$ = phase

We know that, maximum displacement equal to amplitude

Therefore,  $\sin (\omega t + \phi) = 1$

Now, we find the phase at t = 0

$1 = sin \phi$

So, phase will be $\phi = \dfrac{\pi}{2}$