while covering a distance of 30km, Ajeet takes 2 hrs more than Amit. If Amit doubles his speed, he would take 1 hr less than Amit. Find the speed of their walking.
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Speed of ajit = x
Speed of amit = y
Distance is same =30 km
Time of ajit = 30/x
Time of amit =30 / y
A.T.Q when speed of amit= y
30 /x - 30/y =2
When speed of ajit= 2x
Then 30 /y - 30/ 2x
Put x= a
y= s
We get 30a - 30s= 2
-15a+ 30s= 1
Subtracting these two we get
15a= 3
a= 1/5
Now a = x so x = 5
Speed of ajit = 5
Put a = 1/5 in 30 a - 30s= 2
We get 30×1/5-30s =2
4=30s
S= 1/7.5
S= y so speed of amit = 7.5 km / hr
Speed of ajit = 5 km per hour
Speed of amit = y
Distance is same =30 km
Time of ajit = 30/x
Time of amit =30 / y
A.T.Q when speed of amit= y
30 /x - 30/y =2
When speed of ajit= 2x
Then 30 /y - 30/ 2x
Put x= a
y= s
We get 30a - 30s= 2
-15a+ 30s= 1
Subtracting these two we get
15a= 3
a= 1/5
Now a = x so x = 5
Speed of ajit = 5
Put a = 1/5 in 30 a - 30s= 2
We get 30×1/5-30s =2
4=30s
S= 1/7.5
S= y so speed of amit = 7.5 km / hr
Speed of ajit = 5 km per hour
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