Question

The Value of Physical Quantities P and Q for a conductor 4 ohm and 24×10*-8 ohm × m respectively. Write new values of P and Q if length of conductors becomes one - fourth​

Answer 1

If length becomes 1/4  then the value of P will be 1ohm and the value the value of Y will be same i.e Y= 24x10⁻⁸ohm

Explanation:

Let us assume that the length of the conductor will be L.

Its resistance value P = 4ohm.

                                Q = 24x10⁻⁸.ohm

When the length of give substance is reduce to 1/4 , then the material of the substance remains same then the value of Q = 24x10⁻⁸ohm.

Since the area of cross section of the conductor is not charge only length is changed i.e

Length ∝ resistance

So the value of P will be = 4/4 = 1ohm

i.e P = 1ohm and Q = 24x10⁻⁸ohm

Answer 2

P = 1 ohm and Q = 24x10⁻⁸ohm × m

Explanation:

Given data :

Resistance =4 ohm

Resistivity =24×10⁻⁸ ohm×m.

To find the values of P and Q .

If length of conductors become one-fourth,then  it doesn't change the value of area of conductor.

Normally the length is directly proportional to the resistance so it become as,

$\text{P} = \frac{4}{4}$

P = 1 ohm

So,the 1 ohm is the new resistance for the conductor.

The value of Q remains the same when the length is decreased to one fourth of the original size or previous size.

Q = 24x10⁻⁸ohm × m

Therefore the value of physical quantities P and Q are 1 ohm and 24x10⁻⁸ohm, when the length of the substance is decreased to one fourth of its original size.

To learn more ...

1.What is the resistance of a conductor mention the factor of the resistance of a conductor depend

brainly.in/question/5993611

2.What is electric resistance of a conductor ? how is it determined ? name n define its S.I UNIT .

brainly.in/question/776526.