Question

The value of planck's constant is 6.63 x10-34 j sec. The velocity of light is 3 * 10^8 m/s which value is closest to the wavelength in nanometer in quantum of light with frequency of 8* 10^15 sec^-1

Answer 1

Answer:

h=6.63 ×10^-34

c=3×10^8

v=8×10^15

lambda =?

v=hc÷lambda

=8×10^15 =6.623×10^-34×3×10^8÷lambda

=8×10^15=19.869×10^-26÷lambda

=2.48×10^-41 =lambda

hope it helps u...........