Question

the value of plancks constant is 6.63 *10 ^34 Js.the speed of light is 3*10^17n ms^-1.wjich value is closest to the wavelength in nano meter of a quantum of light with frequency of 6*10^15 s^-1?

Answer 1

The formula is as follows :

F = C / Y

F = Frequency

C = Speed of light

Y = Wavelength

Doing the substitution we have :

Y = C/F

= (3 × 10¹⁷) / ( 6 × 10¹⁵) = 0.5 × 10²nm

Answer 2

Explanation:

Given that,

Value of Planck's constant, $h=6.63\times 10^{-34}\ J-s$

Speed of light, $v=3\times 10^{17}\ m/s$

Frequency of light, $\nu=6\times 10^{15}\ Hz$

Let $\lambda$ is the frequency of the light. The relation is as follows :

$v=\nu \lambda$

$\lambda=\dfrac{v}{\nu}$

$\lambda=\dfrac{3\times 10^{17}}{6\times 10^{15}}$

$\lambda=50\ m$

So, the wavelength of the light is 50 meters. Hence, this is the required solution.