The value of polynomial p(x)=4x^2-5x-x^3 at p(0),p(-1)and p2/3)
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hey mate............
here is ur answer.....
p[x]=-x3+4x2-5x
p[0]=[-0]3+4[0]2-5[0]
=0+0-0
=0
p[-1]=[-1]3+4[-1]2-5[-1]
=-1+4+5
=-1+9
=8
p[2/3]=[-2/3]3+4[2/3]2-5[2/3]
= -8/27+16/9-10/3
lcm of 27,9 and 3 is 27
=[-8+48-90]/27
=-50/27
║hope it helps......║
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