the value of remainder when x^2+(a+b)x + ab is divided by (x+b)
Answers
remainder will be zero when x² + (a + b)x + ab is divided by (x + b)
we have to find the remainder when x² + (a + b)x + ab is divided by (x + b).
let's resolve x² + (a + b)x + ab into simpler form.
x² + (a + b)x + ab
= x² + ax + bx + ab
= x(x + a) + b(x + a)
= (x + a)(x + b)
here we see, (x + b) is a factor of x² + (a + b) + ab, so remainder will be zero.
other method :
x + a ) x² + (a + b)x + ab (x + b
x² + ax
.........................
bx + ab
bx + ab
...................
0
hence, remainder = 0
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