the value of sin -1 ( cos 53pie / 5) is
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In your question if it is sin inverse then means you want to know the theta mean :
theta =sin^-1(cos53pie/5)
So take RHS :
Cos53pie/5 can be written as Cos(11pie - 2pie/5) means
(-Cos2pie/5) so your question becomes
: sin^-1(-cos2pie/5)
Value of cos 2pie/5 is √5-1/4
So : sin^-1 (-√5+1/4)
Theta= sin^-1("")
Sin(theta) = 1-√5/4
theta =sin^-1(cos53pie/5)
So take RHS :
Cos53pie/5 can be written as Cos(11pie - 2pie/5) means
(-Cos2pie/5) so your question becomes
: sin^-1(-cos2pie/5)
Value of cos 2pie/5 is √5-1/4
So : sin^-1 (-√5+1/4)
Theta= sin^-1("")
Sin(theta) = 1-√5/4
bblbubbly:
not satisfied
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