Math, asked by harshithjain9780, 5 months ago

The value of sin^2(90°)-tan^2(45°)​

Answers

Answered by jaideepkonka
3

sin 90°= 1

tan 45°= 1

sin^2(90°)-tan^2(45°)

= 1^2-1^2

= 0

Answered by vanshitagoyal1210
1

Answer:

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