Math, asked by peaceisbliss29, 6 months ago


The value of
sin²∅ / cos∅+ cos∅

1
cos∅
sin∅
sec∅​

Answers

Answered by bagkakali
0

Answer:

sin^2 the eta/cos theeta +cos theeta

=(1-cos^2 theeta)/cos theeta+ cos theeta

=1/cos theeta-cos^2theeta/cos theeta+cos theeta

=sec theeta-cos theeta+cos theeta

=sec theeta

Similar questions