Math, asked by leelabhrgav, 4 months ago

the value of sin2a+1/1+tan2a is
plz fast

Answers

Answered by sakeenabeegum0

1

Answer:

= #(1+tan^2A)(1-sin^2A)#

= #sec^2A xx cos^2A#

= #1/cancel(cos^2A)xxcancel(cos^2A)#

= #1#

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