Math, asked by kartikpareek1, 6 months ago

The value of (tan 1° tan2 tan3º... tan89°) is
(a) 0
(b) 1
(c) 2
(d)1/2


give a easy explanation​

Answers

Answered by Heerpatel1405
0

Firstly do paring making it's total of 90°

  • ( tan 1° tan 89°)(tan 2° tan 88°)...

  • (tan 1° tan (90° - 89°))....

  • (tan 1° cot 1°)...
  • 1...

Therefore step by step all upto 89° will be 1 .

so as 1×1×1...= 1 therefor final answer will be 1

Answered by hemanth12313
1

Hope this is helpful

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