Question

The value of (tan 1° tan2 tan3º... tan89°) is
(a) 0
(b) 1
(c) 2
(d)1/2


give a easy explanation​

Answer 1

Firstly do paring making it's total of 90°

• ( tan 1° tan 89°)(tan 2° tan 88°)...

• (tan 1° tan (90° - 89°))....

• (tan 1° cot 1°)...
• 1...

Therefore step by step all upto 89° will be 1 .

so as 1×1×1...= 1 therefor final answer will be 1

Answer 2

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