The value of tan 20 * tan 40 * tan 80 is
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1
Step-by-step explanation:
As we know that
sinθsin(60∘−θ)sin(60∘+θ)=41sin3θ
cosθcos(60∘−θ)cos(60∘+θ)=41cos3θ
tanθtan(60∘−θ)tan(60∘+θ)=cosθsinθ×cos(60∘−θ)sin(60∘−θ)×cos(60∘+θ)sin(60∘+θ)
=cosθcos(60∘−θ)cos(60∘+θ)sinθsin(60∘−θ)sin(60∘+θ)
=41cos3θ41sin3θ=tan3θ
Put θ=20∘
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0
Step-by-step explanation:
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