Math, asked by aryuuthakur, 9 months ago

The value of tan2 (sec-12) + cot? (cosec
13) is
[1 mark]

Answers

Answered by akashreddy12379
0

answer: 11

explanation:

tan2(sec-12) = sec2(sec-12) - 1 cot2(cosec-13) = cosec2(cosec-13) - 1 Therefore, tan2(sec-12) + cot2(cosec-13) = sec2(sec-12) - 1 + cosec2(cosec-13) - 1 = [sec(sec-12)]2 + [cosec(cosec-13)]2 - 2 = (2)2 + (3)2 - 2 = 4 + 9 - 2 = 11. the-value-of-tan2-sec-12-cot2-cosec-13-is

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