The value of (tan60˚+cot60˚)−(sin60˚+cos60˚) is
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Answer- The above question is from the chapter 'Trigonometric Ratios'.
Question: Find the value of (tan60˚ + cot60˚) − (sin60˚ + cos60˚).
Solution: We know that tan 60° = √3
cot 60° = 1/√3
sin 60° = √3/2
cos 60° = 1/2
Substituting values,
(tan60˚ + cot60˚) − (sin60˚ + cos60˚)
= (√3 + 1/√3) - (√3/2 + 1/2)
= (3+1)/√3 - (√3 + 1)/2
= 4√3/3 - √3/ 2 - 1/2
= ( 8√3 - 3√3 - 3)/6
= (5√3 - 3)/6
∴ The value of (tan60˚ + cot60˚) − (sin60˚ + cos60˚) is (5√3 - 3)/6.
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