Question

the value of the discriminant of the equation X square + 1 equal to zero is​

Answer 1

${x}^{2} + 1 = 0 \\ here \: a = 1 \: b = 1 \: c = 0 \\ d = {b }^{2} - 4ac \\ = {1}^{2} - 4(1) \: (0) \\ = 1 \\ d > 0$
two real roots

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Answer 2

hey mate.... here's ur answer

x^2+1=0

discriminant = b^2- 4ac

= 0 - 4 x 1 x 1

= 0 - 4

= -4

hope my answer will help u

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