Question

the value of the function Y= 2x^2- x + 1 at its local minima is​

Answer 1

Answer:

,=7/8

-first find dy/dx=4x-1

-find critical point as put dy/dx=0

=4x-1=0

x=1/4

again find it's 2nd derivative

d^2y/dx^2=4(it is postive it show local minima at x=1/4

and local minimum value is