Question

The value of the polynomial p(x) = 7x^6 + 5x^5 – 3x^2 + 11 at x = 1.

Answer 1

Answer:

The answer is 20

as 7+5-3+11 = 20

Answer 2

Answer:

The required value of the polynomial is $20$.

Step-by-step explanation:

Concept:

Sums of terms of the form $k*x^{n}$, where k is any number and n is a positive integer, make up polynomials. Terms in a polynomial can only be multiplied, added, or removed. $ax^2 + bx + c$, where $a, b,$ and $c$ are real numbers with a $0$, is the formula for a quadratic polynomial in x with real coefficients.

Given:

$p(x) = 7x^6 + 5x^5 -3x^2 + 11$

$x=1$

To find:

We have to find the value of provided polynomial.

Solution:

In this, we have to put $x=1$ in,$p(x) = 7x^6 + 5x^5 -3x^2 + 11$

$p(x) = 7x^6 + 5x^5 -3x^2 + 11\\p(1) = 7(1)^6 + 5(1)^5 -3(1)^2 + 11\\p(1) = 7 + 5 -3 + 11\\p(1) =23-3\\p(1) =20$

Thus, the required value of the polynomial is $20$.

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