Question

The value of 'x' and 'y' when a point lies on the linear equation 2x-3y=12
A. x = 0, y = -3
B. x = 2, y = 3
C. x = 3, y = -2
D. x = -2, y = 3

pls answer correctly u'll get free 20 points...

Answer 1

Given :

 a point lies on the linear equation 2x-3y=12

To Find :  The value of 'x' and 'y'

A. x = 0, y = -3

B. x = 2, y = 3

C. x = 3, y = -2

D. x = -2, y = 3

Solution:

2x-3y=12

x = 0

=> 2(0) - 3y = 12

=> y = - 4

Hence  x = 0, y = -3     is incorrect

2x-3y=12

x = 2

=> 2(2) - 3y = 12

=> -3y = 8

=> y = - 8/3

Hence  x = 2, y =  3     is incorrect

2x-3y=12

x = 3

=> 2(3) - 3y = 12

=> -3y =  6

=> y = - 2

Hence  x = 3  y = -2    is correct

2x-3y=12

x = -2

=> 2(-2) - 3y = 12

=> -3y = 16

=> y = - 16/3

Hence  x = -2, y =  3     is incorrect

so point is         x = 3  y = -2

Learn More:

Ms. Cassidy plotted the point (2, 3) on Miguel's graph of y < 2x – 4 ...

brainly.in/question/13399704

Solve the following x+y/xy=5 and x-5/xy=7 - Brainly.in

brainly.in/question/8168066

Answer 2

Answer:

option c) x = 3 , y = -2

Step-by-step explanation:

put x = 3 in 2x-3y = 12

2(3) - 3y = 12

3y = 6-12 = -6

y = -2

so , option c is correct answer