Question

The value of x for which 2x.(x +10) and (3x + 2) are the three consecutive terms
of an AP.is
(a) 6
(b) -6
2018
(d) -18​

Answer 1

Step-by-step explanation:

Given The value of x for which 2x.(x +10) and (3x + 2) are the three consecutive terms  of an AP.is

• If 2x, x + 10, 3x + 2 are in A.P
• Then x + 10 – 2x = 3x + 2 – x – 10
• So we get – x + 10 = 2x – 8
• Or – 3x = - 18
• Or x = 18 / 3
• Or x = 6

Reference link will be

https://brainly.in/question/10132238

Answer 2

Solution:

Since, 2x, x + 10 , 3x + 2 are in AP.

2x + 20 = 5x + 2

2(x + 10) = 2x + (3x + 2) x = 6

3x = 18

Hope it's Helpful :)