Math, asked by akkysharma501, 1 month ago


The value of x for which 3x,
X+8, 5x+2 are the consecutive
term of an A.P.​

Answers

Answered by aniketkumar467
2

Answer:

7/3

Step-by-step explanation:

We know for AP

a2-a1=a3-a2

so,

x+8-3x=5x+2-(x+8)

=>8-2x=5x+2-x-8

=>8-2x=4x-6

=>8+6=4x+2x

=>14=6x

=> x=14/6=7/3

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