Math, asked by bermudagalaxy2009, 9 months ago

The Value of X in 142XxX5=20X5X142​

Answers

Answered by yashasvee009
1

Answer:

The values of x are

To find : The value of x?

Solution :

Let y=x^2y=x 2

in the given equation x^4-142x^2+1=0x 4 −142x 2+1=0

So, (x^2)^2-142(x^2)+1=0(x 2 ) 2 −142(x 2 )+1=0

y^2-142y+1=0y  2 −142y+1=0

Solve by quadratic formula,

Here, a=1, b=-142 and c=1

Now substitute in y=x^2y=x 2

When

Therefore, the values of x are

Step-by-step explanation:

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Answered by happin2005
0

Answer:

given, 142*x*5=20*5*142

when I multiple 142&5,we got 710

Then, we multiply 20&142&5,we got 14200

So, 710*x=14200

X=14200/710

X=1420/71.

I hope you got the answer.

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