Math, asked by kunalmalik0101201839, 7 months ago

the value of x in the figure is ​

Answers

Answered by nanditapsingh77
0

Answer:

Where is the figure???

??????

Answered by Mihir1001
34

 \underline{ \huge\bf\red{QuestiØn} :}

Find x .

 \boxed{ \sqrt{3}x - 2 = 2 \sqrt{3}   + 4}

 \underline{ \: \huge\bf\green{SolutiØn} \: :}

We have,

\begin{aligned}  \\  &  \qquad \ \ \ x \sqrt{3}   - 2 = 2 \sqrt{3} + 4 \\  \\  &  \implies x \sqrt{3} - 2 \sqrt{3}   = 2 + 4 \\  \\  &   \implies(x - 2) \sqrt{3}  = 6 \\  \\ & \implies x - 2 =  \frac{6}{ \sqrt{3} }   \\  \\  &  \implies x - 2 =  \frac{2 \sqrt{3} \times  \cancel{ \sqrt{3}}  }{ \cancel{ \sqrt{3}} }  \\  \\  &  \implies x - 2 = 2 \sqrt{3}  \\  \\  & \implies x = 2 \sqrt{3}  + 2 \\  \\   & \implies x = 2( \sqrt{3} + 1) \\  \\   &   \large\mathfrak{Hence} , \\  &  \underline{ \boxed{x = 2( \sqrt{3}  + 1)}}\end{aligned}

\red{\rule{5.8cm}{0.02cm}}

\mid \underline{\underline{\LARGE\bf\green{Brainliest \: Answer}}}\mid

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