Question

the value of 'x' in the given figure is

A) 116
B) 60
C) 126
D)101​

Answer 1

Answer:

the answer is 126 because there is multiple of opposite and then add

Answer 2

The value of "x" in the given figure is :-

(A) 116

(B) 60

(C) 126 ☑

(D) 101

${ \purple{ \rm{How \: to \: Solve?}}}$

Here, in this question, first we will multiply both the opposite numbers on either four sides with each other and then after getting the product of each factor, we will add both the products together and find the number that is at the centre.

${ \purple{ \rm{ \underline{ \underline{Step \: by \: step \: Explanation : }}}}}$

⚘ In case ① :-

Let us first multiply both the opposite numbers on either four sides,

➯ $\blue{ \rm{ 4 \times 4 = 16}}$

➯ $\blue{ \rm{5 \times 6 = 30}}$

Now, let us add both the products together.

◑ $\blue{ \rm{16 + 30 = 46}}$

∴ In first case value of number at the centre

$\green{\Large{ \underline{ \boxed{ \tt{ \blue{ = 46}}}}}}$

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⚘ In case ② :-

Again Let us first multiply both the opposite numbers on either four sides,

➯ $\blue{ \rm{5 \times 5 = 25}}$

➯ $\blue{ \rm{7 \times 8 = 56}}$

Again add both the products together, we have:

◑ $\blue{ \rm{25 + 56 = 81}}$

∴ In second case the value of number at the centre

$\green{\Large { \underline{ \boxed{ \tt{ \blue{ = 81}}}}}}$

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⚘ In case ③ :-

Again multiply both the opposite numbers on either four sides,

➯ $\blue{ \rm{6 \times 6 = 36}}$

➯ $\blue{ \rm{9 \times 10 = 90}}$

Now add both the products together,

◑ $\blue{ \rm{36 + 90 = 126}}$

∴ In third case the value of number at the centre

$\green{\Large{ \underline{ \boxed{ \tt{ \blue{ = 126}}}}}}$

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