Question

the value of x which makes the following statement true is :
(3 7/11 × 11/5) ÷ (3/7×x)
a) 7/2
b) 14
c) 7
d) 28​

Answer 1

Step-by-step explanation:

Let us solve it by using 4 values in the place of x.

a) 7/2

$\frac{3 \frac{7}{11} \times \frac{11}{5} }{ \frac{3}{7} \times \frac{7}{2} } \\ = \frac{ \frac{40}{11} \times \frac{11}{5} }{ \frac{3}{2} } \\ = \frac{8}{ \frac{3}{2} } \\ = 8 \times \frac{2}{3} \\ = \bf{ \underline{ \underline{ \frac{16}{3} }}}$

b) 14

$\frac{3 \frac{7}{11} \times \frac{11}{5} }{ \frac{3}{7} \times 14} \\ = \frac{ \frac{40}{11} \times \frac{11}{5} }{ 6 } \\ = \frac{8}{ 6 } \\ = \bf{ \underline{ \underline{ \frac{4}{3} }}}$

c) 7

$\frac{3 \frac{7}{11} \times \frac{11}{5} }{ \frac{3}{7} \times 7 } \\ = \frac{ \frac{40}{11} \times \frac{11}{5} }{ 3} \\ = \bf{ \underline{ \underline{ \frac{8}{3} }}}$

d) 28

$\frac{3 \frac{7}{11} \times \frac{11}{5} }{ \frac{3}{7} \times 28 } \\ = \frac{ \frac{40}{11} \times \frac{11}{5} }{ 12 } \\ = \frac{8}{12} \\ = \bf{ \underline{ \underline{ \frac{2}{3} }}}$