Question

The value of ( x-y)3+(y-z)3+(z-x)3/9(x-y)(y-z)(z-x)

Answer 1

Here’s your answer i.e. 0

Please mark my answer as Brainliest

Answer 2

Answer:

Step-by-step explanation:

If a+ b+C=0

Then a^3+b^3+c^3=3abc

Let

x-y=a

y-z=b

z-x=c

x-y+y-z+z-x=0

So

(x-y)^3+(y-z)^3+(z-x)^3=3(x-y)(y-z)(z-x)

Hence

= 3(x-y)(y-z)(z-x)/9(x-y)(y-z)(z-x)

= 1/3