The value of y^x-x^y+xy= when x=6,,y=2
Answers
Answered by
1
Answer:
40 is the answer
Step-by-step explanation:
y^x-x^y+xy
= 2^6-6^2+6(2)
=64-36+12
=40
Answered by
0
Answer: 40
Step-by-step explanation:
x=6
y=2
then,
2^6 - 6^2 + 6×2
= 64 - 36 + 12
= 28 + 12
= 40
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