Math, asked by asim26, 1 year ago

the value of z the equation is z^10-33z^5+32=0

Answers

Answered by kcharan1459
0
Simplifying z10 + -33z5 + 32 = 0 Reorder the terms: 32 + -33z5 + z10 = 0 Solving 32 + -33z5 + z10 = 0 Solving for variable 'z'. Factor a trinomial. (1 + -1z5)(32 + -1z5) = 0

Subproblem 1

Set the factor '(1 + -1z5)' equal to zero and attempt to solve: Simplifying 1 + -1z5 = 0 Solving 1 + -1z5 = 0 Move all terms containing z to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1z5 = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1z5 = 0 + -1 -1z5 = 0 + -1 Combine like terms: 0 + -1 = -1 -1z5 = -1 Divide each side by '-1'. z5 = 1 Simplifying z5 = 1 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Subproblem 2

Set the factor '(32 + -1z5)' equal to zero and attempt to solve: Simplifying 32 + -1z5 = 0 Solving 32 + -1z5 = 0 Move all terms containing z to the left, all other terms to the right. Add '-32' to each side of the equation. 32 + -32 + -1z5 = 0 + -32 Combine like terms: 32 + -32 = 0 0 + -1z5 = 0 + -32 -1z5 = 0 + -32 Combine like terms: 0 + -32 = -32 -1z5 = -32 Divide each side by '-1'. z5 = 32 Simplifying z5 = 32 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be
Answered by rajsushantrp4ulkn
8

Here is the simple answer

Attachments:
Similar questions