Question

the sides of a triangle are 13 1/2 m,11 3/4m and 3 3/8m find the perimeter

Answer 1

Refer to the above attachment

Answer 2

Sides =
$13 \frac{1}{2} = \frac{27}{2} \\ \\ 11 \frac{3}{4} = \frac{47}{4} \\ \\ 3 \frac{3}{8} = \frac{27}{8}$
perimeter = sum of all sides

=> perimeter =
$\frac{27}{2} + \frac{47}{4} + \frac{27}{8} \\ \\ = > \frac{108}{8} + \frac{94}{8} + \frac{27}{8} \\ \\ = \frac{229}{8} \\ \\ = 28\frac{5}{8}$
hope it helps dear friend ☺️✌️