the valueof(2+J5) (2-J3) is
Answers
Answered by
0
Answer:
19+j4
Step-by-step explanation:
=(2+j5) *(2-j3)
=4+j10-j6-j^2 15
=19+j4
Answered by
5
Answer:
=> (2+J5) ( 2-J3) = 0
=> 2(2-J3)+J5(2-J3) =0
=>4-6J + 10 J - 15J^2= 0
=> 4-4J - 15J^2 = 0
=>0 = 15J^2 +4J -4
=>15J^2 + 4J - 4 = 0
This is your answer....
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