Math, asked by mariyambiabduljabbar, 9 months ago

the valueof(2+J5) (2-J3) is​

Answers

Answered by shaukatalijauhar
0

Answer:

19+j4

Step-by-step explanation:

=(2+j5) *(2-j3)

=4+j10-j6-j^2 15

=19+j4

Answered by mantasakasmani
5

Answer:

=> (2+J5) ( 2-J3) = 0

=> 2(2-J3)+J5(2-J3) =0

=>4-6J + 10 J - 15J^2= 0

=> 4-4J - 15J^2 = 0

=>0 = 15J^2 +4J -4

=>15J^2 + 4J - 4 = 0

This is your answer....

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