Question

the values of a & b so that the polynomial x3 – ax2 – 13x + b is divisible by (x – 1) and (x – 3) are?

Answer 1

Answer:

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Step-by-step explanation:

Let p(x) = x3 – ax2 – 13x + b be the given polynomial.

If (x – 1) and (x + 3) are the factors  of  p(x) then

p(1) = 0

and  p(-3) = 0

p(1) = (1)3 – a(1)2 – 13(1) + b = 0

= 1 – a – 13 + b = 0

a – b =  -12

p(-3)  = (- 3)3 – a(- 3)2  - 13(- 3) + b = 0

= - 27 – 9a + 39 + b = 0

9a – b = 12    ….(2)

Solving (1) and (2) we get

a = 3

and  b = 15

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Answer 2

Answer:

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Step-by-step explanation:

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