Question

the values of angle acb and angle adb if 'O' is the center of the circle and angle aob = 160
​

Answer 1

Step-by-step explanation:

In the cyclic quadrilateral ABCD

∠BCD=

2

1

∠BOD

[Angle made by an arc at the centre is double the angle made by it, at any other point on the remaining part of the circle]

∴∠x=

2

1

×160

∘

=80

∘

∴x=80

∘

∠x+∠y=180

∘

[opp. angles of a cyclic quadrilateral]

∴∠y=180

∘

−∠x

∠y=180

∘

−80

∘

=100

∘

y=100

∘