The values of current I flowing in a given resistor for the corresponding values of potential difference V across the resistor are given below -
I (amperes) - 0.5 - 1.0 - 2.0 - 3.0 - 4.0
V(volts) - 1.6 - 3.4 - 6.7 - 10.2 - 13.2
Plot a graph between V and I and calculate the resistance of that resistor.
Answers
According to the ohm’s law, we can get the value of V as RI.
Hence the resistance of the resistor is taken as R.
The calculation for the resistance is given below.
R = (V2- V1) / I2 – I1
R = (6.7 – 3.4) / 2.0 – 1.0
R = 3.3 V / 1.0 A
Hence, the resistance of the resistor R = 3.3 Ω.
Answer:
V - I graph as shown in figure . Here points lie on the equation of line {where variables are V and I } are (1.6 ,0.5) , (3.4,1.0) , (6.7, 2.0) , (10.2, 3.0) and (13.2, 4.0)
Now , use Ohm's law ,
V = IR
R = V/I , means Resistance is the slope of graph V - I
So, R = (V₂ - V₁)/(I₂ - I₁)
V₂ = 3.4V, V₁ = 1.6V , I₂ = 1A and I₁ = 0.5A
So, R = (3.4 - 1.6)/(1 - 0.5) = 1.8/0.5 = 3.6
Hence, resistance , R = 3.6Ω
similarly R= (V₃ - V₂)/(I₃ - I₂) = (6.7 - 3.4)/(2 - 1) = 3.3
R = (V₄ - V₃)/(I₄ - I₃) = (10.2 -6.7)/(3-2) = 3.5
R=(V₅ - V₄)/(I₅ - I₄) = (13.2 - 10.2)/(4-3) = 3
here R is variable so, take average of all . Rav = (3.6 + 3.3 + 3.5 + 3)/4 = 13.4/4 = 3.35Ω
hence, resistance = 3.35Ω
Explanation: