Question

The values of electronegativity of atoms a and b are 1.20 and 4.0 respectively. The percentage of ionic character of a b bond is

Answer 1

Answer:

72.24‬

Explanation:

by hanny smith equation;

%ionic character = 16(change in electronegativity) + 3.5 ( change in electronegaticity)^2

so. = 16(2.8) + 3.5(2.8)^2 = 72.24%