The values of Planck's constant is 6.63 x 10^-34Js. The
velocity of light is 3.0 x 10^8 ms-1. Which value is closest to
the wavelength in nanometres of a quantum of light with
frequency of 8 x 10^15/s?
Answers
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1
Solution:-
As we know that,
ν=
λ
c
⇒λ=
ν
c
where,
λ = wavelength of a quantum of light = ?
ν = frequency of a quantum of light = 8×10
15
s
−1
c = speed of light = 3×10
8
m/s
∴λ=
8×10
15
3×10
8
=0.375×10
−7
m=3.75×10
1
nm(∵1m=10
9
nm)
Hence, 4×10
1
will be the closest value to the wavelength (in nm) of a quantum of light with frequency 8×10
15
s
−1.
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