Question

The van't hoff factor for 0.1 m ba(no3)2 solution is 2.74. the degree of dissociation is

Answer 1

use the formula
$\alpha = \frac{i - 1}{n - 1}$
here I=2.74 and n=3

Answer 2

Explanation:

$\alpha = \frac{i \: − \: 1}{n \: - \: 1} \\ \: \: \: \: \:= \frac{2.74 \: - \: 1}{3 - 1} \\ = 0.87 \\ = 87\%$

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