Question

The Van't Hoff factor of acetic acid in water will be

Answer 1

Acetic acid ionizes as CH3COOH⇌CH3COO−+H+
CH3COOH=1−αCH3COOH=1−α
CH3COO−=α
H+=α
It produces (1+α) species from one CH3COOH
Since α<1 the van't hoff factor will lie in between 1 and 2
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Answer 2

Answer : The Van't Hoff factor of acetic acid in water will be, 2

Explanation :

Van't Hoff factor is the ratio of number of particles after association to the number of particles before association.

$i=\frac{\text {observed colligative property}}{\text {Calculated Colligative property}}$

For 100% dissociation of a solute, van't Hoff factor is equal to the number of ions produces from one molecule of the solute.

For $CH_3COOH$ :

$CH_3COOH\rightarrow H^++CH_3COO^-$

After dissociation : the number of ions produced = 1 + 1 = 2

So, the Van't Hoff factor, $i=2$

Therefore, the Van't Hoff factor of acetic acid in water will be, 2