Question

The van't Hoff factor of the compound K3Fe(CN)6 in dilute solution is​

Answer 1

The dissociative equation for K3[Fe(CN)6 can be written as under

K3[Fe(CN)6]→3K++[Fe(CN)6]3−

Therefore the number of particles after dissociation =4

So van't hoff factor =4/1=4

Answer 2

The dissociative equation for K3[Fe(CN)6 can be written as under

K3[Fe(CN)6]→3K++[Fe(CN)6]3−

Therefore the number of particles after dissociation =4

So van't hoff factor =4/1=4

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