Question

The van't Hoff's factor of 0.1M Ba (NO2)2 solution is 2.74. The degree
of dissociation is-​

Answer 1

Answer:

Let degree of dissociation be x.

x = (i - 1)/(n - 1)

Ba(NO2)2 ---> Ba2+ + 2NO2-

Here n = 3

x = ( 2.74 - 1 )/2

= > x = 1.74/2

= > x = 0.87

Answer 2

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