the vant hoff s of 0.1M Ba(NO2)2 solution is 2.74 the degree of dissociation
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If the vent vent hoff factor is 2 .74 then the dissociation is 0.87.
Formula is dissociation =
i - 1 /n - 1 ,here n is 3.
Formula is dissociation =
i - 1 /n - 1 ,here n is 3.
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